If 8.96 mol of c₅h₁₂ reacts with excess o₂, how many moles of co₂ will be produced by the following combustion reaction?
c₅h₁₂ + 8 o₂ ⟶ 6 h₂o + 5 co₂

There will be produced 44.8 moles of CO2

Explanation:

Step 1: Data given

Number of C5H12 = 8.96 moles

O2 is in excess, this means C5H12 is the limiting reactant

Molar mass of C5H12 = 72.15 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

C₅H₁₂ + 8 O₂ ⟶ 6 H₂O + 5 CO₂

This means for 1 mol C5H12 we need 8 moles of O2 to produce 6 moles H2O and 5 moles CO2

Step 3: Calculate moles of CO2

Since C5H12 is the limiting reactant.

For 1 mol C5H12 we need 8 moles of O2 to produce 6 moles H2O and 5 moles CO2

For 8.96 moles C5H12 we'll have 5*8.96 = 44.8 moles

There will be produced 44.8 moles of CO2

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.