Asample of carbon monoxide occupies 4.63 l at 296.0 k and 737 torr. find its volume at −29°c and 432 torr.

The new volume at -29°C and 432 torr is 6.51 L

Explanation:

Step 1: Data given

Initial volume of CO = 4.63 L

Initial temperature = 296.0 K

Initial pressure = 737 torr = 737/760 = 0.9697 atm

Step 2: Calculate the new volume

(P1*V1)/T1  = (P2*V2)/T2

V2 = (P1V1*T2) / (T1*P2)

⇒ with P1 = the initial pressure = 0.9697 atm

⇒ with V1 = the initial volume = 4.63 L

⇒ with T1 = The initial temperature = 296.0 K

⇒ with T2 = the new temperature = -29.0 + 273 = 244 K

⇒ with P2 = the new pressure = 432/760 = 0.5684 atm

V2 = (P1V1/T1) * (T2/P2)

V2 = 6.51 L

The new volume at -29°C and 432 torr is 6.51 L

i do not get it   at all