Calculate the ph of a solution formed by mixing 20.00 ml of 0.30 m hcl with 30.00 ml of 0.15 m hno3? ?

0.68

Explanation:

Both and are strong acids which ionize completely in water. According to stoichiometry, 1 mole of each will produce 1 mole of hydronium cations. Therefore, let's calculate the total number of moles of hydronium and find the final concentration of it keeping in mind the dilution:

Total molarity:

Find pH:

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm