Calculate the ph of 0.005 methonoic acid solution given that the degree of dissociation is 0.057

pH = 2.77

Explanation:

Data Given:

degree of dissociation Ka = 0.057

Concentration of Methanoic acid = 0.005 M

pH = ?

Solution:

First we calculate Hydrogen ion concentration

Formula will be used

             [H⁺] = . . . . . . (1)

where

Ka = degree of dissociation

c = concentration

Put values in formula 1

                        [H⁺] = . . . . . . (1)

                        [H⁺] = 0.0017 M

Now Calculate the pH

As we know

          pH = -log [H⁺] . . . . . .(2)

Put values in equation

           pH = - log [ 0.0017 M]

           pH = - [-2.77]

           pH =    2.77

So,

pH of methanoic acid =    2.77      

the only liquid elements at standard temperature and pressure are bromine (br) and mercury (hg). although, elements caesium (cs), rubidium (rb), francium (fr) and gallium (ga) become liquid at or just above room temperature.

explanation:

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.