How many grams of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 12.0 g of hydrochloric acid?

The answer to your question is 29.7 g of CaCl₂

Explanation:

data

mass CaCl₂ = ?

mass CaCO₃ = 27 g

mass HCl = 12 g

Balanced Reaction

                           CaCO₃  +  HCl   ⇒   CaCl₂  + H₂O  +  CO₂

Molecular weight

CaCO₃ = 40 + 12 + 48 = 100 g

HCl = 36 + 1 = 37 g

- Calculate proportions

Theoretical proportion CaCO₃ / HCl  = 100 / 37 = 2.7

Experimental proportion  CaCO₃/ HCl = 27/12 = 2.25

From the proportions we determine that the limiting reactant is CaCO₃, because the proportion diminishes.

Molecular weight CaCl₂  = 40 + 35.5 = 110 g

                             100 g CaCO₃   110 g of CaCl₂

                             27 g CaCO₃    x

                             x = (27 x 110) / 100

                             x = 29.7 g of CaCl₂