Radon is a naturally occurring radioactive gas found in the ground and in building materials. it is easily inhaled and emits alpha particles when it decays. cumulative radon exposure is a significant risk factor for lung cancer. calculate the density of radon at 277 k and 0.950 atm of pressure.

9.28 g/L

Explanation:

We will be using the ideal gas law to solve this problem:

PV = nRT where P is the pressure (atm)

                           V is the volume (L)

                           R is the gas constant 0.08205 Latm/Kmol

                           T is the temperature (K)

                           n is the number of moles

The number of moles is the mass divided by the molecular weight, and from here we can solve for the density. (Note here we use the atomic weight of radon since its is a monoatomic noble gas)

PV = m/AW RT ⇒  P = (m/V ) RT/AW ⇒   P AW /RT =D

0.950 atm x 222.0 g/mol / [( 0.08205 Latm/Kmol ) x 277 K ] = D

9.28 g/L = D

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.