0.456 grams of a monoprotic acid is titrated with 45.88 ml of 0.0500 m naoh. what is the molecular mass (molar mass) of the acid

Explanation:

Considering:

Given :

For NaOH :

Molarity = 0.0500 M

Volume = 45.88 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 45.88×10⁻³ L

Moles of NaOH = Moles of monoprotic acid

So, moles of monoprotic acid = 0.002294 moles

Given that:- mass = 0.456 g

The formula for the calculation of moles is shown below:

Thus,

i'm pretty sure its b i might be wrong though!