How many molecules are in 1.00 g of c10h14n2? 3.71 x 1021 9.76 x 1025 1.02 x 10-26 2.32 x 1022

3.71 x 1021 (First option)

Explanation:

Let's determine the molar mass of the compound.

C₁₀H₁₄N₂ = 12. 10 + 14 .1 + 14 .2 = 162 g/mol

So 162 grams of compound are contained in 1 mol

1 g of  C₁₀H₁₄N₂ are contained in ( 1 / 162) = 0.00617 moles

Let's conver the moles into amount of molecules (mol . NA)

0.00617 . 6.02×10²³ = 3.71×10²¹ molecules