Which represents the balanced nuclear equation for the beta plus decay of c-11?
superscript 11 subscript 6 upper c right arrow superscript 11 subscript 5 upper b plus superscript 0 subscript plus 1 e.
superscript 11 subscript 6 upper c right arrow superscript 11 subscript 7 upper n plus superscript 0 subscript plus 1 e.
superscript 11 subscript 6 upper c right arrow superscript 11 subscript 7 upper n plus superscript 0 subscript negative 1 e.
superscript 11 subscript 6 upper c right arrow superscript 11 subscript 5 upper b plus superscript 0 subscript negative 1 e.

Superscript 11 subscript 6 upper C right arrow superscript 11 subscript 5 upper B plus superscript 0 subscript plus 1 e.

Explanation:

Beta decay:

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.  In beta positive decay proton is converted into neutron and positron, thus the atomic number is decreased by one.

¹¹₆C → ¹¹₅B + ⁰₊₁e

In beta minus decay the one electron is ejected and neutron is converted into proton.

¹⁴₆C → ¹⁴₇N + ⁰₋₁e

Properties of beta radiations:

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation .

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.