What is the molality of a solution formed by dissolving 1.12 mol of kcl in 16.0 mol of water?

The molality of the solution is 3.45 mol/kg

Explanation:

Molality is a type of concentration which shows the moles of solute contained in  1 kg of solvent.

Moles of salt (KCl) = 1.12 moles

Moles of solvent (H₂O) = 18 moles

Let's convert the moles of solvent to mass (mol . molar mass)

18 m . 18g/m = 324 grams

We convert grams to kg → 324 g / 1000 = 0.324 kg

Now we can reach molality

1.12mol / 0.324 kg = 3.45 m

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

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