At a certain temperature the vapor pressure of pure heptane is measured to be . suppose a solution is prepared by mixing of heptane and of acetyl bromide .

This is an incomplete question, here is a complete question.

At a certain temperature the vapor pressure of pure heptane is measured to be 170 torr. Suppose a solution is prepared by mixing 86.7 g of heptane and 125 g of acetyl bromide.

Calculate the partial pressure of heptane above this solution. Round your answer to 3 significant digits.

Answer : The partial pressure of heptane is, 78.2 torr

Explanation : Given,

Mass of heptane = 86.7 g

Mass of acetyl bromide = 125 g

Molar mass of heptane = 100 g/mole

Molar mass of acetyl bromide = 122.9 g/mole

First we have to calculate the moles of heptane and acetyl bromide.

and

Now we have to calculate the mole fraction of heptane and acetyl bromide.

and

Now we have to partial pressure of heptane.

where,

= partial pressure of heptane

= total pressure of gas

= mole fraction of heptane

Therefore, the partial pressure of heptane is, 78.2 torr

i'm not sure

explanation:

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