If the molten nacl is replace dby an 1.0m aqueous sodium chloride solution how much sodium can be collected if a curret of 1.0 a is applied for 1.0 hour?

0.89 g

Explanation:

The knowledge of Faraday's second law of electrolysis is generally required here; the law states that when the same quantity of electricity is passed through a solution of different electrolyte, the mass of the substance deposited is directly proportional to it's chemical equivalence.

NOTE: 1 Farads  (F) = 96,500 Coloumbs (C)

What this law means is that,

Generally, the quantity of electricity required to displace potassium (K) from a compound is 96500C because the charge of K is 1+ while the quantity of electricity required to displace calcium (Ca) from a solution is 2 x 96500 because the charge of Ca is 2+.

To the question,

the quantity of electricity required to displace 23g (atomic mass of sodium) of sodium from a solution is 96,500 C because the charge of sodium is 1+. However, when a current of 1A is applied to a solution containing sodium for one hour, the quantity of electricity that passes through the solution is

Q = It  (Faraday's first law of electrolysis)

I = current

t = time in secs hence 1 hour = 1 x 60 x 60 = 3,600 s

Q = 1 x 3,600 =3,600 C

Hence, if 96,500 C will displace 23 g of sodium

3, 600 C will displace ??

From the above,

?? = 23 x 3,600/96,500

?? = 0.89 g

3,600 C will displace 0.89g of sodium (which can hence be collected)

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