What mass of oxygen gas is produced by the reaction of 3.8 g of ammonium perchlorate?

There is 1.29 grams of O2 produced.

Explanation:

Step 1: Data given

Mass of ammonium perchlorate 3.8 grams

Molar mass of ammonium perchlorate = 117.49 g/mol

Step 2: The balanced equation

4NH4ClO4 → 5O2 + 6H2O + 2N2 + 4HCl

Step 3: Calculate moles of NH4ClO4

Moles NH4ClO4 = mass NH4ClO4 / molar mass NH4ClO4

Moles NH4ClO4 = 3.80 grams / 117.49 g/mol

Moles NH4ClO4 = 0.0323 moles

Step 4: Calculate moles of O2

For 4 moles of ammonium perchlorate consumed, we produce 5 moles O2, 6 moles H2O, 2 moles N2 and 4 moles HCl

For 0.0323 moles NH4ClO4 we'll have 5/4 * 0.0323 = 0.040375 moles of O2

Step 5: Calculate mass of O2

Mass O2 = moles O2 * molar mass O2

Mass O2 = 0.040375 moles * 32 g/mol

Mass O2 = 1.29 grams

There is 1.29 grams of O2 produced.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.