Give the outer electron configuration for each of the following columns in the periodic table. 1a,2a,5a,7a express your answer as a string without blank space between orbitals. for example, the outer electron configuration for the column 4a, ns2np2, should be entered as ns^2np^2.

1A:  ns^1

2A: ns^2

5A: ns^2np^3

7A: ns^2np^5  

Explanation:

According to IUPAC, the columns 1A, 2A, 5A, and 7A correspond to the groups, 1, 2, 15 and 17, respectively.

The outer electron configuration of these columns are the following:

Column    Outer electron configuration

1A              ns^1

2A             ns^2

5A             ns^2np^3

7A             ns^2np^5  

Therefore, for the column 1A the s orbital has only one electron, for the column 2A has the s orbital completed with 2 electrons, for the column 5A the number of electrons in the s orbital is complete (2) and the number of electrons in the p orbital is 3, for the column 7A the s orbital has 2 electrons and the p orbital has 5 electrons.            

I hope it helps you!                      

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally