A1.30m solution of bacl2 has a density of 1.230 g/ml. a) what is the mole fraction of bacl2 in this solution?

The mole fraction of barium chloride in the solution is 0.024

Explanation:

We are given:

Molarity of barium chloride solution = 1.30 M

This means that 1.30 moles of barium chloride is present in 1 L or 1000 mL of solution.

Density of solution = 1.230 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

    .....(1)

Moles of barium chloride = 1.30 moles

Molar mass of barium chloride = 208 g/mol

Putting values in equation 1, we get:

Mass of water = Mass of solution - Mass of barium chloride

Mass of water = 1230 - 270.4 = 959.6 g

Calculating the moles of water:

Given mass of water = 959.6 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

Mole fraction of a substance is given by:

Hence, the mole fraction of barium chloride in the solution is 0.024

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