Chemistry, 23.01.2020 22:31 iv267829

Assuming that all the h comes from hcl, how many grams of sodium hydrogen carbonate will totally neutralize the stomach acid?

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Answer from: rosieposie27

The question is incomplete, here is the complete question:

Assuming that all the H^+ comes from HCl, how many grams of sodium hydrogen carbonate will totally neutralize the stomach acid? Volume = 500 mL pH= 2

The mass of sodium hydrogen carbonate needed to completely neutralize stomach acid is 0.42 grams

Explanation:

To calculate the hydrogen ion concentration of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

pH = 2

Putting values in above equation, we get:

$2=-\log[H^+]$

$[H^+]=10^{-2}M$

To calculate the number of moles for given molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of hydrogen ions = 0.01 M

Volume of solution = 500 mL = 0.5 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.01M=\frac{\text{Moles of hydrogen ions}}{0.5L}\\\\\text{Moles of hydrogen ions}=(0.01mol/L\times 0.5L)=0.005mol$

The chemical equation for the reaction of HCl and sodium hydrogen carbonate follows:

$HCl+NaHCO_3\rightarrow NaCl+H_2CO_3$

By Stoichiometry of the reaction:

1 mole of HCl reacts with 1 mole of sodium hydrogen carbonate

So, 0.005 moles of HCl will react with = $\frac{1}{1}\times 0.005=0.005mol$ of sodium hydrogen carbonate

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of sodium hydrogen carbonate = 0.005 moles

Molar mass of sodium hydrogen carbonate = 84 g/mol

Putting values in above equation, we get:

$0.005mol=\frac{\text{Mass of sodium hydrogen carbonate}}{84g/mol}\\\\\text{Mass of sodium hydrogen carbonate}=(0.005mol\times 84g/mol)=0.42g$

Hence, the mass of sodium hydrogen carbonate needed to completely neutralize stomach acid is 0.42 grams

Answer from: Quest

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

$^{m}_{4}x$ and $^{m}_4y$

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

$^{m}_{5}x^{-}$

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be $^{9}_{5}be^{-}$ and $^{9}_{4}be$ .

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.

Answer from: Quest

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