Cu + al2o3à al + cuofor this unbalanced chemical equation, what is the coefficient for aluminum oxide (al2o3) when the equation is balanced?

The coefficient of Al2O3 is 1

Explanation:

Step 1: Data given

The unbalanced equation: Cu + Al2O3 → Al + CuO

Step 2: Balancing the equation

On the left side we have 2x Al (in Al2O3) on the right side we have 1x Al. To balance the amount of Al, we have to multiply Al on the right side by 2

Cu + Al2O3 → 2Al + CuO

On the left side we have 3x O (in Al2O3), on the right side we have 1x O (in CuO). To balance the amount of O, we have to multiply CuO on the right side, by 3

Cu + Al2O3 → 2Al + 3CuO

On the right side we have 3x Cu (in 3CuO), on the left side we have 1x Cu. To balance the amount of Cu on both sides, we have to multiply Cu (on the left side) by 3.

Now the equation is balanced.

3Cu + Al2O3 → 2Al + 3CuO

The coefficient of Al2O3 is 1

your answer would be “dry”

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year