A8-kg plastic tank that has a volume of 0.18 m3 is filled with liquid water. assuming the density of water is 1000 kg/m3, determine the weight of the combined system.

1.84 × 10³ N

Explanation:

To determine the weight of the system, we will determine its mass which is equal to the sum of the masses of the plastic tank (8 kg) and the water.

We have 0.18 m³ of water with a density of 1000 kg/m³. Its mass is:

0.18 m³ × 1000 kg/m³ = 180 kg

The mass of the system is 180 kg + 8 kg = 188 kg.

We can find the weight (w) of the system using Newton's second law of motion.

w = m × g = 188 kg × 9.81 m/s² = 1.84 × 10³ N

where

g is the gravity

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.