A1.000 l vessel is filled with 1.000 mole of n2,2.000 moles of h2, and 3.000 moles of nh3. when the reaction n2(g) + 3 h2(g)⇀↽2 nh3(g) comes to equilibrium, it is observed that the concentration of nh3is 2.12 moles/l. what is the numerical value of the equilibrium constant kc?

The numerical value of equilibrium constant is 0.0560

Explanation:

Initial Concentration:

 = 3M

[] = 1M

[] = 2 M

at the end, [] = 1.96 M

Thus the change is 3 - 1.96  = 1.04 M

Thus 1.04 moles of  reacted

By stoichiometry, 1.04 moles  () = 0.52 mol created (in addition to 1 mol already in vessel)

By similar reasoning   = 1.56 moles  created  

Final concentrations:

[] = 1.96 M

[] = 0.52 + 1 = 1.52 M

[] = 1.56 + 2  = 3.56 M

0.0560

Therefore, the numerical value of equilibrium constant is 0.0560

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'