Citrate synthase catalyzes the reaction: + − → + − the standard free energy change for the reaction is −31.5 ∙ −1. calculate the equilibrium constant for this reaction at 37℃.

The given question is incomplete. The complete question is as follows.

Citrate synthase catalyzes the reaction

Oxaloacetate + acetyl-CoA citrate + HS-CoA

The standard free energy change for the reaction is -31.5 kJ*mol^-1

( a) Calculate the equilibrium constant for this reaction a 37degrees C

Explanation:

(a).  It is known that , relation between change in free energy () of a reaction and equilibrium constant (K) is as follows.

where,  T = temperature in Kelvin

The given data is as follows.

         T = 310 K,        (as 1 kJ = 1000 J)

Now, putting the given values into the above formula as follows.

     ln K =

            =

      ln K = 12.22

         K = antilog (12.22)

           =

Therefore, we can conclude that value of equilibrium constant for the given reaction is .

h let me think

the answer is learned