A30-0 g sample of water at 280 k is mixed with 50.0 g of water at 330 k. how would you calculate the final temperature of the mixture assuming no heat is lost to the surroundings?

311.25k

Explanation:

The question assumes heat is not lost to the surroundings, therefore

heat emitted from hotter sample ( )= heat absorbed by the less hotter  sample( )

The relationship between heat (q), mass (m) and temperature (t) is

where c is specific heat capacity, temperature change.

=

equating both heat emitted and absorb

where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.

C will cancel out since both are water and they have the same specific heat capacity.

so we have

where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?

-50 * ( - 330) = 30 *  ( - 280)

-50 + 16500 = 30 - 8400

80 = 16500+8400

80 = 24900

= 24900/80 = 311.25k

answer: any goods being imported from another country may be subject to issued by the federal government are tariffs

explanation:  

tariffs are a tax on anything that are imported from abroad. government use them to protect and boost their local industries and the thought is that they encourage consumers to buy local instead of importing and they will hope will protect jobs and economy in the country that implements them  

i think it's letter a.