The specific heat of a certain type of metal is 0.128j/(g.°c). what is the final temperature if 305 j of hear is added to 28.8 g of this metal, initially at 20.0°c?

Temperature final = 103 °C

Explanation: To solve for final temperature we use the equation of heat:

Q= mc∆T

Next derive the equation to find final temperature

Q = mc(T final - T initial)

Q / mc = T final - T initial

Transpose T initial and change the sign so that T final will be left.

T final = Q / mc + T initial

Substitute the values:

T final = 305 J / 28.8 g x 0.128 J/(g°C)

= 305 J / 3.6864 J/°C

= 82.7 + 20.0°C

= 103 °C final temperature.

it can be icreased by increasing pressure.

the answer would be b i believe