What mass (in g) of solute is contained in 764.9 ml of a 0.137 m solution of glucose, c6h12o6? enter your answer with 3 significant figures and no units.

18.9

Explanation:

Given data

We can find the moles (n) of glucose using the following expression.

n = C × V

n = 0.137 mol/L × 0.7649 L

n = 0.105 mol

The molar mass of glucose is 180.16 g/mol. The mass corresponding to 0.105 moles is:

m = 0.105 mol × 180.16 g/mol = 18.9 g

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