What volume of propane (c3h8) is required to produce 165 liters of water according to the following reaction? (all gases are at the same temperature and pressure.) propane (c3h8) (g) + oxygen(g)carbon dioxide (g) + water(g)

We need 41.2 L of propane

Explanation:

Step 1: Data given

volume of H2O = 165 L

Step 2:  The balanced equation

C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

Step 3: Calculate moles of H2O

1 mol = 22.4 L

165 L = 7.37 moles

Step 4: Calculate moles of propane

For 1 mol C3H8 we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O

For 7.37 moles H2O we need 7.37/4 = 1.84 moles propane

Step 5: Calculate volume of propane

1 mol = 22.4 L

1.84 moles = 41.2 L

We need 41.2 L of propane

i just learnt this recently but i need to look through my notes again

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.