Isopropyl alcohol is mixed with water to produce a 32.0 % (v/v) alcohol solution. how many milliliters of each component are present in 795 ml of this solution

The volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL

Explanation:

We are given:

32.0 % (v/v) alcohol solution

This means that 32 mL of isopropyl alcohol is present in 100 mL of solution

Volume of water = 100 - 32 = 68 mL

Volume of solution given = 795 mL

Applying unitary method:

In 100 mL of solution, the volume of isopropyl alcohol present is 32 mL

So, in 795 mL of solution, the volume of isopropyl alcohol present will be =

Volume of water in given amount of solution = 795 - 254.4 = 540.6 mL

Hence, the volume of isopropyl alcohol present is 254.4 mL and the volume of water present is 540.6 mL

there are no statements provided but here is why:

sulfur belongs to group 16 because it can be found in nature whether it is in a free or combined state.

hope this