You measure out 14.66 ml of vinegar solution. you used 13.58 ml of 0.115 m naoh solution to titrations to the endpoint. what what the lol story of the vinegar solution?

Molarity of Vinegar solution is 0.107 M

Explanation:

Let V1 be the volume of NaOH = 13.58 ml

Let V2 be the volume of Vinegar = 14.66 ml

Let M1 be the molarity of NaOH = 0.115 M

Let M2 be the molarity of Vinegar = ?

Using the Law of Volumetric analysis, V1M1= V2M2

Rearranging the equation to get M2 as,

M2 = V1M1/V2 = 13.58 ml * 0.115 M/14.66 ml = 0.107 M

So the Molarity of Vinegar = 0.107 M

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