How much heat must be absorbed by 125 of ethanol to change its temperature from 22.3 to 31.0 ? (specific heat capacity of ethanol is 2.42 )

a. 2.63×103kj
b. 4.55 kj
c. 85.2 kj
d. 2.63 kj

The heat = 2.63 kJ (option d)

Explanation:

Step 1: Data given

Mass of ethanol = 125 grams

Initial temperature of ethanol = 22.3 °C

Final temperature of ethanol = 31.0 °C

Specific heat of ethanol = 2.42 J/g°C

Step 2: Calculate heat transfer

Q = m*c*ΔT

⇒ with Q = the heat transfer (in joules)

⇒ with m = the mass of ethanol = 125 grams

⇒ with c = the specific heat of ethanol = 2.42 J/g°C

⇒ with ΔT = The change of temeprature = T2 - T1 = 31.0 - 22.3 °C = 8.7 °C

Q = 125 grams * 2.42 J/g°C *  8.7 °C

Q = 2632 J = 2.63 kJ

The heat = 2.63 kJ (option d)

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explanation: