What mass in grams, of aluminum fins could 3088j of energy heat from 14.77 degrees c to 26.31 degrees c? aluminum has a specific heat of 0.897/j (g degrees celsius)?

                     298.32 grams

Explanation:

                     Amount of energy required by known amount of a substance to raise its temperature by one degree is called specific heat capacity.

The equation used for this problem is as follow,

                                                Q  =  m Cp ΔT    (1)

Where;

          Q  =  Heat  =  3088 J

          m  =  mass  =  ??

          Cp  =  Specific Heat Capacity  =  0.897 J.g⁻¹.°C⁻¹

          ΔT  =  Change in Temperature  =  26.31 °C  -  14.77 °C  =  11.54 °C

Solving eq. 1 for m,

                               m  =  Q / Cp ΔT

Putting values,

                               m  =  3088 J / (0.897 J.g⁻¹.°C⁻¹ × 11.54 °C)

                               m  =  298.32 g

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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