If 50.0 g of KCl reacts with 50.0 g of O2 to produce KCLO3 according to the following equation how many grams of KCLO3 will be formed

2.2 grams

Explanation:

2KCl + 3O2 --> 2KClO3

KCl = 39+ 35.5

   = 74.5 g/mol

O = 16 g/mol so O2 is 32 g/mol

We need 3 mols of O2 for every 2 mols of KCl

50 g KCl = 50/74.5 = .671 mols of KCl

we need .671 * 3/2 = 1.007 mols of O2 = 32 g

Now we have more O2 than we need, just use the .671 mols of KCl, limiting reagent

now

We get 1 mol KClO3 for every mol of KCl

then we get .671 mols of KClO3

74.5 + 3*16 = 122.5 grams/mol of KClO3

.671 * 122.5 = 2.2 grams

h

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .