A commercial grade aqueous HCl solution is 37.0% (by mass) HCl and has a density of 1.18 g/mL. What is the molality of the HCl solution?

Molality is 16.1 m

Explanation:

37 % by mass indicates that 37 g of HCl, our solute, is contained in 100 g of solution. Let's determine the mass of solvent.

Mass of solution = Mass of solute + Mass of solvent

100 g = 37 g + Mass of solvent

Mass of solvent is 63 g

Let's convert the mass to kg → 63 g . 1kg / 1000 g = 0.063kg  for molality

Let's convert the mass of solute to moles → 37 g . 1 mol / 36.45 g = 1.01 moles of solute

Molality → mol/kg = 1.01 mol / 0.063 kg → 16.1 m

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph