An object of mass 10.0 kg is initially at rest. A 100 N force causes it to move horizontally through a distance of 6.00 m. What is the change in the kinetic energy of this object?

The answer to the question is

The change in the kinetic energy of the object is 600 J

Explanation:

The known variables are,

Mass of object, m = 100 kg

Force of object, F = 100 N

The relation for kinetic energy = KE = = 0.5·m·v²

Therefore to find v we first find the acceleration from

F = m·a =10.0 kg × a = 100 N,

Where a = acceleration of the object =100/10 = 10 m/s²

To find the velocity, v, we use the relationship

v² = u² + 2 × a × S, where S is the distance of motion = 6.00 m and u is the initial velocity, u = 0 m/s, therefore

v² = 0 + 2 × 10 m/s² × 6 m = 120 m²/s² or v = 10.95 m/s

Therefore KE = 0.5 × 10 kg × (10.95 m/s)² = 600 J

where the initial velocity, u = 0 m/s

Initial kinetic energy of the object = KE₁ = 0.5 × 10 × 0² = 0

The change in kinetic energy of the object = 600 J - 0 J = 600 J

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you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6