If a 0.760 m aqueous solution freezes at − 3.60 ∘ C, what is the van't Hoff factor, i , of the solute?

The van't Hoff factor is 2.55

Explanation:

Step 1: Data given

molality = 0.760 molal

The aqueous solution freezes at -3.60 °C

Kb of water = 1.86°C/m

Step 2: Calculate the van't Hoff factor

ΔT = i*Kb*m

3.60 = i * 1.86 * 0.760

i = 3.60( 1.86*0.760)

i = 2.55

The van't Hoff factor is 2.55

what does the table look like