4. A 1,750 kg weather satellite moves in a circular orbit with a gravitational

potential energy of 1.69 x 100 J. At its location, free-fall acceleration is only

6.44 m/s?. How high above Earth's surface is the satellite?

Explanation:

It is known that the value of free fall acceleration is g = 6.44 . And, the value of radius of Earth is .

Let us assume that height of the satellite is h.

It is known that,

             g =        

where,   r = (R + h)

Hence,  

              r =

              r =

                =

Now, formula for height of satellite above the Earth's surface is as follows.

            h = r - R

               =

               =

Thus, we can conclude that the satellite is high above Earth's surface.

i'm assuming that it's c.) red bank..