A mixture of MnCl2 and inert material is analyzed to determine the Mn content. First the mixture is dissolved in water. Then all of the chloride ion is precipitated as AgCl by the addition of an excess of silver nitrate. MInCl2(aq) _ 2AgNO3(aq)- :2AgCI(s)-Mn(NO3)2(aq) In one experiment, a 0.7094 g sample of the mixture resulted in 1.3651 g of AgCI Determine the percent (by mass) of Mn in the mixture. % Mn
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A mixture of MnCl2 and inert material is analyzed to determine the Mn content. First the mixture is...
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