What is the volume of the air in a balloon that occupies 0.620 L at 25*C if the temperature is lowered to 0.00 *C. (assuming the pressure remains constant)

0.568L

Explanation:

V1 = 0.620 L

T1 = 25°C = 25 +273 = 298K

V2 =?

T2 = 0°C = 273K

V1 /T1 = V2 / T2

0.620/298 = V2 / 273

Cross multiply

298 x V2 = 0.620 x 273

Divide both side by the coefficient V2 ie 298, we have

V2 = (0.620 x 273) /298

V2 = 0.568L

Therefore, the volume of the air when the temperature is reduced to 0°C is 0.568L

the equation that correctly represent the reaction for formation of ammonia is

n2+ 3h2 → 2nh3 (answer d)

1 mole of nitrogen gas (n2) react with 3 moles of hydrogen gas (h2) to form 2 moles of ammonia ( nh3). this is in a process known as haber process were iron is used as a catalyst and reaction take place that a higher temperature and pressure. the process is exothermic hence energy is released.

1 a

2 d

3 a

4 c

explanation: