Nitrogen and hydrogen react to form ammonia according to the following balanced equation: N2(g) + 3H2(g) → 2NH3(g) Calculate the number of moles of hydrogen required to react with 0.0763 mole of nitrogen, and the number of moles of ammonia that will form.

0.0763 moles of nitrogen will react with  0.2289 moles of hydrogen to form  0.1526 moles of ammonia.

The balanced chemical reaction has been able to find the number of moles of reactant and product.

The given balanced equation will be:

From the equation, 1 mole of nitrogen reacts with 3 moles of hydrogen to form  2 moles of ammonia is formed.

0.0763 moles of Nitrogen = 0.0763 3 moles of Hydrogen

0.0763 moles of nitrogen = 0.2289 moles of Hydrogen

Thus, for 0.0763 moles of Nitrogen, 0.2289 moles of Hydrogen is required to form ammonia.

From the balanced chemical equation,

0.0763 moles of Nitrogen =  0.0763 2 moles of Ammonia

0.0763 moles of Nitrogen = 0.1526 moles of ammonia.

Thus, 0.0763 moles of nitrogen will form 0.1526 moles of ammonia.

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It is required 0.2289 moles of H₂ and it's been produced 0.1526 moles of NH₃

Explanation:

Reaction is: N₂(g) + 3H₂(g)  → 2NH₃(g)

Ratio in the reactants is 1:3

So 1 mol of nitrogen needs 3 moles of hydrogen for the reaction

0.0763 moles may need (0.0763 . 3)/1 = 0.2289 moles of H₂

In the reaction ratio is 1:2, or 3:2. It is the same if we use the nitrogen or the hydrogen.

1 mol of N₂ produces 2 moles of ammonia

0.0763 mol of N₂ will produce 0.1526 moles of ammonia

3 moles of H₂ produce 2 moles of amonia

0.2289 moles of H₂ may produce (0.2289 . 2)/3 = 0.1526 moles of NH₃