Chemistry, 11.02.2020 23:08 oliviaschmitt0

Twelve grams of carbon combine chemically with 4 grams of hydrogen to produce a
combustible gas. What is the empirical formula of this gas?
O A. C2H4
© B. CH3
OC. CH
OD. CH

Answers: 3

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Answer from: brandonholden

Empirical Formula = C₁H₄ or CH₄

Explanation:

Data Given:

Mass of C = 12.0 g

Mass of H = 4 g

Step 1: Calculate Moles of each Element;

Moles of C = Mass of C ÷ At.Mass of C

Moles of C = 12.0 ÷ 12.0

Moles of C = 1.0 mol

Moles of H = Mass of H ÷ At.Mass of H

Moles of H = 4.0 ÷ 1.0

Moles of H = 4.0 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 53.924 ÷ 16.0

Moles of O = 3.370 mol

Step 2: Find out mole ratio and simplify it;

C H

1.0 4.0

1.0/1.0 4.0/1.0

1 4

Hence,

Empirical Formula = C₁H₄ or CH₄

Answer from: Quest

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

Answer from: Quest

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

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Twelve grams of carbon combine chemically with 4 grams of hydrogen to produce a
combustible ga...

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