Determine the molality of an aqueous solution prepared by dissolving 0.112 moles of licl in 13.7 moles of h2o.

Molality is 0.45 mol/kg for the LiCl

Explanation:

Molality → Moles of solute in 1kg of solvent

Let's convert the moles of solvent, water to mass (g)

Afterwards we need to convert the mass from g to kg

Molality → mol / kg

First step: 13.7 mol . 18 g / 1mol = 246.6 g

2nd step: 246.6 g . 1kg / 1000 g = 0.2466 kg

Molality → mol/kg → 0.112 moles / 0.2466 kg → 0.45 molal

the answer would be c

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.