At 450 K the rate constant is 15.4 atm-1s-1. How much time (in s) is needed for NOCl originally at a partial pressure of 56 torr to decay to 14.5 torr?

This is an incomplete question, here is a complete question.

Consider the second-order decomposition of nitroysl chloride:

At 450 K the rate constant is 15.4 atm⁻¹s⁻¹. How much time (in s) is needed for NOCl originally at a partial pressure of 53 torr to decay to 10.6 torr?

Answer : The time needed for NOCl is, 2.52 seconds.

Explanation :  Given,

Rate constant =

Initial partial pressure of NOCl = 56 torr = 0.0737 atm

final partial pressure of NOCl = 14.5 torr = 0.0191 atm

The expression used for second order kinetics is:

where,

k = rate constant

t = time

= concentration at time 't'

= initial concentration

As we know that,

Thus, the expression of second order kinetics will be:

As,

So,         ............(1)

Now put all the given values in the above expression 1, we get:

Therefore, the time needed for NOCl is, 2.52 seconds.

indium, and thallium have three electrons i think

periodic trends is an atom that gets larger as the number of electronic shells increase, the radius of atoms increases as you go down a certain group in the periodic table of elements. in general, the size of an atom will decrease as you move from left to right of a certain period.