A solution is prepared by dissolving 25.00 g of sodium chloride (NaCl) in 850.0 g of water. What is the molality of NaCl in this solution?

The molality is 0.504 molal

Explanation:

Step 1: Data given

Mass of NaCl = 25.00 grams

Molar mass NaCl = 58.44 g/mol

Mass of water = 850.0grams

Step 2: Calculate moles NaCl

Moles NaCl = mass NaCl / molar mass NaCl

Moles NaCl = 25.0 grams / 58.44 g/mol

Moles NaCl = 0.428 moles

Step 3: Calculate molality

Molality = moles NaCl / mass H2O

Molality = 0.428 moles / 0.850 kg

Molality = 0.504 molal

The molality is 0.504 molal

a basic solution is an aqueous solution containing more oh-ions than h+ions. in other words, it is an aqueous solution with a ph greater than 7. basic solutions contain ions, conduct electricity, turn red litmus paper blue, and feel slippery to the touch.

explanation:

answer: your mm

explanation: