Which is not a process involved in the formation of sedimentary rock?

deposition

extrusion

weathering

compaction

B. Extrusion

Explanation:

Extrusion process is not involved in the process of formation of sedimentary rocks. These rocks are formed by following processes -

1) weathering of preexisting rocks

2) transport of the weathering products

3) deposition of the material

4) compaction

5) cementation of the sediment to form a rock

At the point when rocks are at or close to the outside of the earth they are presented to the procedures of weathering. Sediments are deposited layer upon layer. The layers are kept evenly. As sedimentation proceeds, the prior stored residue are weighed down with an expanding overburden. They are compacted, diminishing the accessible pore space and removing a significant part of the pore-water.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

m=9

step-by-step explanation: