The Fischer esterification mechanism is examined in the following two questions in the assignment. Part 1 involves MeOH addition to form the key tetrahedral intermediate. Part 2 will involve loss of H2O to form the ester.

The mechanism is observed in the attached file.

Explanation:

It begins with the protonation of the carbonyl group of the carboxylic acid. Then, methanol attacks the protonated carbonyl group and forms a tetrahedral intermediate, which by a proton exchange process forms a tetrahedral intermediate that has water. The expulsion of water is produced by the regeneration of the carbonyl group, in addition to the formation of the protonated ester. Finally, the proton exchange with the water molecule regenerates the acid catalyst.

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.