Calcium carbonate can be decomposed by heating: CaCO3 - CaO + CO2
what is the theoretical yield of CaO if 24.8g of calcium carbonate were heated?

13.888g

Explanation:

CaCO3 —> CaO + CO2

From the equation above, 1mole of CaCO3 produces 1mole of CaO. Since the answer is to be expressed in grams, let us covert this mole to grams. This is illustrated below:

MM of CaCO3 = 40 +12 + (16x3) = 40 + 12 + 48 = 100g/mol

MM of CaO = 40 + 16 = 56g/mol

From the equation,

100g of CaCO3 produced 56g CaO

Therefore, 24.8g of CaCO3 will produce Xg of CaO i.e

Xg of CaO = (24.8 x 56) / 100 = 13.888g

Therefore, the theoretical yield of CaO is 13.888g

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).