A 56-kg hiker is climbing the 828-m-tall Burj Khalifa in Dubai. If the efficiency of converting the energy content of the bars into the work of climbing is 25%, the remaining 75% of the energy released through metabolism is heat released to her body. She eats two energy bars, one of which produces 1.10×103kJ of energy upon metabolizing. Assume that the heat capacity of her body is equal to that for water (75.3 Jmol−1⋅K−1). Calculate the increase in her temperature at the top of the structure.

The given question is incomplete. The complete question is as follows.

A 56-kg hiker is climbing the 828-m-tall Burj Khalifa in Dubai. If the efficiency of converting the energy content of the bars into the work of climbing is 25%, the remaining 75% of the energy released through metabolism is heat released to her body. She eats two energy bars, one of which produces 1.10×103kJ of energy upon metabolizing. Assume that the heat capacity of her body is equal to that for water (75.3 Jmol−1⋅K−1). Calculate the increase in her temperature at the top of the structure.

Calculate the temperature at the top of the structure. Assume her intitial temperature to be .

Explanation:

Energy present in total of two bars is as follows.

          kJ

            (as 1 kJ = 1000 J)

As 75% of energy releases out. Let us assume that energy releases out of its body be E. Then, energy will be calculated as follows.

       E =

          = J

Given data is as follows.

       mass (m) = 56 kg

                       = 56000 g   (1 kg = 1000 g)

 Specific heat = 4.18

As heat is releasing which means that value of E will be negative.

        -E =  

Her temperature at the top of the structure is .

Now, change in temperature is calculated as follows.

                            =

Thus, we can conclude that increase in her temperature at the top of the structure is .