If a gas is cooled from 425.0K to 275.15K and the volume is kept constant what final pressure would result if the original pressure was 770.0 mm Hg?

498.51mmHg

Explanation:

First let us analyse what was given from the question:

T1 = 425K

T2 = 275.15K

P1 = 770 mmHg

P2 =?

Using the general gas equation

P1V1/T1 = P2V2/T2

But we were told from the question that the volume is constant. So, our equation becomes:

P1/T1 = P2/T2

770/425 = P2 /275.15

Cross multiply to express in linear form:

P2 x 425 = 770 x 275.15

Divide both side by 425, we have:

P2 = (770 x 275.15) /425

P2 = 498.51mmHg

the answer is na (sodium)

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.