Rate = k[AB]2 and k = 0.20 L/mol·s. If the initial concentration of AB is 1.50 M, what is [AB] after 14.0 s?

Answer : The concentration of AB after 14.0 s is, 0.29 M

Explanation :

The expression used for second order kinetics is:

where,

k = rate constant =

t = time = 14.0 s

= final concentration = ?

= initial concentration = 1.50 M

Now put all the given values in the above expression, we get:

Therefore, the concentration of AB after 14.0 s is, 0.29 M

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