Calculate the molality of a 35.0% (by mass) aqueous solution of nitric acid. 6.64 538 8.55 3.32 The density of the solution is needed to solve the problem.

43.452

step-by-step explanation:

284 times .153 = 43.452

catya that's not even a b or c

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally