What is the entropy change (in J/K) of 71 g of steam at 100°C when it condenses to water at the same temperature?

Answer : The change in entropy is

Explanation :

Formula used :

where,

= change in entropy = ?

m = mass of water = 71 g

= heat of vaporization of water =

T = temperature =

Now put all the given values in the above formula, we get:

Therefore, the change in entropy is

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

catya your not at all which answer i've seen you do this on another question!