Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3 ( is ) . The equation for the reaction is 2 KClO3 ⟶ 2 KCl + 3 O 2 Calculate how many grams of O 2 ( g ) can be produced from heating 66.8 g KClO 3 ( s ) .

The answer to your question is  52.35 g of O₂

Explanation:

mass of oxygen = ?

mass of KClO₃ = 66.8 g

Chemical balanced reaction

              KClO₃   ⇒   2 KCl  +   3O₂

Process

1.- Calculate the molar mass of KClO₃ and Oxygen

KClO₃ = 39 + 35.5 + (16 x 3) = 122.5 g

O₂ = 16 x 6 = 96 g

2.- Write proportions to solve this problem

                     122.5 g of KClO₃  96 g of O₂

                        66.8 g                x

                        x = (66.8 x 96) / 122.5

                        x = 6412.8/122.5

                        x = 52.35 g of O₂

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

pie chart because it is in percents ( % )