Nitrogen monoxide, NO, reacts with hydrogen, H2, according to the following equation. 2 NO + 2 H2 → N2 + 2 H2O What would the rate law be if the mechanism for this reaction were as follows? (Rate expressions take the general form: rate = k . [A]a . [B]b.) 2 NO + H2 → N2 + H2O2 (slow) H2O2 + H2 → 2 H2O (fast)

The rate law for the reaction is

Explanation:

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

The intermediate reaction of the mechanism follows:

Step 1:  

Step 2:  

As, step 1 is the slow step. It is the rate determining step

Rate law for the reaction follows:

Hence, the rate law for the reaction is